3x+4+11(1-4x)=1+x-2(x-16)

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Solution for 3x+4+11(1-4x)=1+x-2(x-16) equation: 



3x+4+11(1-4x)=1+x-2(x-16)

We move all terms to the left:

3x+4+11(1-4x)-(1+x-2(x-16))=0

We add all the numbers together, and all the variables

3x+11(-4x+1)-(1+x-2(x-16))+4=0

We multiply parentheses

3x-44x-(1+x-2(x-16))+11+4=0



We calculate terms in parentheses: -(1+x-2(x-16)), so:

1+x-2(x-16)

determiningTheFunctionDomain
x-2(x-16)+1

We multiply parentheses

x-2x+32+1

We add all the numbers together, and all the variables

-1x+33

Back to the equation:

-(-1x+33)



We add all the numbers together, and all the variables

-41x-(-1x+33)+15=0

We get rid of parentheses

-41x+1x-33+15=0

We add all the numbers together, and all the variables

-40x-18=0

We move all terms containing x to the left, all other terms to the right

-40x=18

x=18/-40

x=-9/20

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