4(3x+1)-(x-2)=13

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Solution for 4(3x+1)-(x-2)=13 equation: 



4(3x+1)-(x-2)=13

We move all terms to the left:

4(3x+1)-(x-2)-(13)=0

We multiply parentheses

12x-(x-2)+4-13=0

We get rid of parentheses

12x-x+2+4-13=0

We add all the numbers together, and all the variables

11x-7=0

We move all terms containing x to the left, all other terms to the right

11x=7

x=7/11

x=7/11

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