10(x+2)=(x-1)-6x

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Solution for 10(x+2)=(x-1)-6x equation: 



10(x+2)=(x-1)-6x

We move all terms to the left:

10(x+2)-((x-1)-6x)=0

We multiply parentheses

10x-((x-1)-6x)+20=0



We calculate terms in parentheses: -((x-1)-6x), so:

(x-1)-6x

We add all the numbers together, and all the variables

-6x+(x-1)

We get rid of parentheses

-6x+x-1

We add all the numbers together, and all the variables

-5x-1

Back to the equation:

-(-5x-1)



We get rid of parentheses

10x+5x+1+20=0

We add all the numbers together, and all the variables

15x+21=0

We move all terms containing x to the left, all other terms to the right

15x=-21

x=-21/15

x=-1+2/5

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