4(3v-2)-(2v-6)=18

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Solution for 4(3v-2)-(2v-6)=18 equation: 



4(3v-2)-(2v-6)=18

We move all terms to the left:

4(3v-2)-(2v-6)-(18)=0

We multiply parentheses

12v-(2v-6)-8-18=0

We get rid of parentheses

12v-2v+6-8-18=0

We add all the numbers together, and all the variables

10v-20=0

We move all terms containing v to the left, all other terms to the right

10v=20

v=20/10

v=2

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