10b-2(b+3)=5b+

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Solution for 10b-2(b+3)=5b+ equation: 



10b-2(b+3)=5b+

We move all terms to the left:

10b-2(b+3)-(5b+)=0

We add all the numbers together, and all the variables

10b-2(b+3)-(+5b)=0

We multiply parentheses

10b-2b-(+5b)-6=0

We get rid of parentheses

10b-2b-5b-6=0

We add all the numbers together, and all the variables

3b-6=0

We move all terms containing b to the left, all other terms to the right

3b=6

b=6/3

b=2

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