4(3v+2)=3(2v-1)

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Solution for 4(3v+2)=3(2v-1) equation: 



4(3v+2)=3(2v-1)

We move all terms to the left:

4(3v+2)-(3(2v-1))=0

We multiply parentheses

12v-(3(2v-1))+8=0



We calculate terms in parentheses: -(3(2v-1)), so:

3(2v-1)

We multiply parentheses

6v-3

Back to the equation:

-(6v-3)



We get rid of parentheses

12v-6v+3+8=0

We add all the numbers together, and all the variables

6v+11=0

We move all terms containing v to the left, all other terms to the right

6v=-11

v=-11/6

v=-1+5/6

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