117=3+2(8b+-7)

Solution for 117=3+2(8b+-7) equation:

117=3+2(8b+-7)

We move all terms to the left:

117-(3+2(8b+-7))=0

We add all the numbers together, and all the variables

-(3+2(8b-7))+117=0


We calculate terms in parentheses: -(3+2(8b-7)), so:

3+2(8b-7)

determiningTheFunctionDomain
2(8b-7)+3

We multiply parentheses

16b-14+3

We add all the numbers together, and all the variables

16b-11

Back to the equation:

-(16b-11)


We get rid of parentheses

-16b+11+117=0

We add all the numbers together, and all the variables

-16b+128=0

We move all terms containing b to the left, all other terms to the right

-16b=-128

b=-128/-16

b=+8