4(3s+2)=128

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Solution for 4(3s+2)=128 equation: 



4(3s+2)=128

We move all terms to the left:

4(3s+2)-(128)=0

We multiply parentheses

12s+8-128=0

We add all the numbers together, and all the variables

12s-120=0

We move all terms containing s to the left, all other terms to the right

12s=120

s=120/12

s=10

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