176=(x+12)(x-8)(4)

Solution for 176=(x+12)(x-8)(4) equation:

176=(x+12)(x-8)(4)

We move all terms to the left:

176-((x+12)(x-8)(4))=0

We multiply parentheses ..

-((+x^2-8x+12x-96)4)+176=0


We calculate terms in parentheses: -((+x^2-8x+12x-96)4), so:

(+x^2-8x+12x-96)4

We multiply parentheses

4x^2-32x+48x-384

We add all the numbers together, and all the variables

4x^2+16x-384

Back to the equation:

-(4x^2+16x-384)


We get rid of parentheses

-4x^2-16x+384+176=0

We add all the numbers together, and all the variables

-4x^2-16x+560=0

a = -4; b = -16; c = +560;
Δ = b2-4ac
Δ = -162-4·(-4)·560
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-96}{2*-4}=\frac{-80}{-8}
=+10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+96}{2*-4}=\frac{112}{-8}
=-14
$