4(3r-4)=3(r-9)+2

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Solution for 4(3r-4)=3(r-9)+2 equation: 



4(3r-4)=3(r-9)+2

We move all terms to the left:

4(3r-4)-(3(r-9)+2)=0

We multiply parentheses

12r-(3(r-9)+2)-16=0



We calculate terms in parentheses: -(3(r-9)+2), so:

3(r-9)+2

We multiply parentheses

3r-27+2

We add all the numbers together, and all the variables

3r-25

Back to the equation:

-(3r-25)



We get rid of parentheses

12r-3r+25-16=0

We add all the numbers together, and all the variables

9r+9=0

We move all terms containing r to the left, all other terms to the right

9r=-9

r=-9/9

r=-1

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