2(4x+6+2x-2)=28

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Solution for 2(4x+6+2x-2)=28 equation: 



2(4x+6+2x-2)=28

We move all terms to the left:

2(4x+6+2x-2)-(28)=0

We add all the numbers together, and all the variables

2(6x+4)-28=0

We multiply parentheses

12x+8-28=0

We add all the numbers together, and all the variables

12x-20=0

We move all terms containing x to the left, all other terms to the right

12x=20

x=20/12

x=1+2/3

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