4(3n-2)+8(n+1)=100

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Solution for 4(3n-2)+8(n+1)=100 equation: 



4(3n-2)+8(n+1)=100

We move all terms to the left:

4(3n-2)+8(n+1)-(100)=0

We multiply parentheses

12n+8n-8+8-100=0

We add all the numbers together, and all the variables

20n-100=0

We move all terms containing n to the left, all other terms to the right

20n=100

n=100/20

n=5

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