7x-2-4x-5=3(x-1)-4

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Solution for 7x-2-4x-5=3(x-1)-4 equation: 



7x-2-4x-5=3(x-1)-4

We move all terms to the left:

7x-2-4x-5-(3(x-1)-4)=0

We add all the numbers together, and all the variables

3x-(3(x-1)-4)-7=0



We calculate terms in parentheses: -(3(x-1)-4), so:

3(x-1)-4

We multiply parentheses

3x-3-4

We add all the numbers together, and all the variables

3x-7

Back to the equation:

-(3x-7)



We get rid of parentheses

3x-3x+7-7=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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