4(3n+2)=6(3-n)+8

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Solution for 4(3n+2)=6(3-n)+8 equation: 



4(3n+2)=6(3-n)+8

We move all terms to the left:

4(3n+2)-(6(3-n)+8)=0

We add all the numbers together, and all the variables

4(3n+2)-(6(-1n+3)+8)=0

We multiply parentheses

12n-(6(-1n+3)+8)+8=0



We calculate terms in parentheses: -(6(-1n+3)+8), so:

6(-1n+3)+8

We multiply parentheses

-6n+18+8

We add all the numbers together, and all the variables

-6n+26

Back to the equation:

-(-6n+26)



We get rid of parentheses

12n+6n-26+8=0

We add all the numbers together, and all the variables

18n-18=0

We move all terms containing n to the left, all other terms to the right

18n=18

n=18/18

n=1

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