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X(8X-29)=12
We move all terms to the left:
X(8X-29)-(12)=0
We multiply parentheses
8X^2-29X-12=0
a = 8; b = -29; c = -12;
Δ = b2-4ac
Δ = -292-4·8·(-12)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-35}{2*8}=\frac{-6}{16} =-3/8 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+35}{2*8}=\frac{64}{16} =4 $
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