4(3n+1)=7(7n+4)+7

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Solution for 4(3n+1)=7(7n+4)+7 equation: 



4(3n+1)=7(7n+4)+7

We move all terms to the left:

4(3n+1)-(7(7n+4)+7)=0

We multiply parentheses

12n-(7(7n+4)+7)+4=0



We calculate terms in parentheses: -(7(7n+4)+7), so:

7(7n+4)+7

We multiply parentheses

49n+28+7

We add all the numbers together, and all the variables

49n+35

Back to the equation:

-(49n+35)



We get rid of parentheses

12n-49n-35+4=0

We add all the numbers together, and all the variables

-37n-31=0

We move all terms containing n to the left, all other terms to the right

-37n=31

n=31/-37

n=-31/37

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