4(3k-6)-2(5k+3)=3-2(k+2)

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Solution for 4(3k-6)-2(5k+3)=3-2(k+2) equation: 



4(3k-6)-2(5k+3)=3-2(k+2)

We move all terms to the left:

4(3k-6)-2(5k+3)-(3-2(k+2))=0

We multiply parentheses

12k-10k-(3-2(k+2))-24-6=0



We calculate terms in parentheses: -(3-2(k+2)), so:

3-2(k+2)

determiningTheFunctionDomain
-2(k+2)+3

We multiply parentheses

-2k-4+3

We add all the numbers together, and all the variables

-2k-1

Back to the equation:

-(-2k-1)



We add all the numbers together, and all the variables

2k-(-2k-1)-30=0

We get rid of parentheses

2k+2k+1-30=0

We add all the numbers together, and all the variables

4k-29=0

We move all terms containing k to the left, all other terms to the right

4k=29

k=29/4

k=7+1/4

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