4(3c+4)=8(1c-2)

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Solution for 4(3c+4)=8(1c-2) equation: 



4(3c+4)=8(1c-2)

We move all terms to the left:

4(3c+4)-(8(1c-2))=0

We add all the numbers together, and all the variables

4(3c+4)-(8(c-2))=0

We multiply parentheses

12c-(8(c-2))+16=0



We calculate terms in parentheses: -(8(c-2)), so:

8(c-2)

We multiply parentheses

8c-16

Back to the equation:

-(8c-16)



We get rid of parentheses

12c-8c+16+16=0

We add all the numbers together, and all the variables

4c+32=0

We move all terms containing c to the left, all other terms to the right

4c=-32

c=-32/4

c=-8

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