4(3c+4)=(c-2)

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Solution for 4(3c+4)=(c-2) equation: 



4(3c+4)=(c-2)

We move all terms to the left:

4(3c+4)-((c-2))=0

We multiply parentheses

12c-((c-2))+16=0



We calculate terms in parentheses: -((c-2)), so:

(c-2)

We get rid of parentheses

c-2

Back to the equation:

-(c-2)



We get rid of parentheses

12c-c+2+16=0

We add all the numbers together, and all the variables

11c+18=0

We move all terms containing c to the left, all other terms to the right

11c=-18

c=-18/11

c=-1+7/11

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