4(3c+1)=40

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Solution for 4(3c+1)=40 equation: 



4(3c+1)=40

We move all terms to the left:

4(3c+1)-(40)=0

We multiply parentheses

12c+4-40=0

We add all the numbers together, and all the variables

12c-36=0

We move all terms containing c to the left, all other terms to the right

12c=36

c=36/12

c=3

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