1/2(4x-20)=1/3(-6x+3)

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Solution for 1/2(4x-20)=1/3(-6x+3) equation: 



1/2(4x-20)=1/3(-6x+3)

We move all terms to the left:

1/2(4x-20)-(1/3(-6x+3))=0



Domain of the equation: 2(4x-20)!=0

x∈R





Domain of the equation: 3(-6x+3))!=0

x∈R



We calculate fractions


(3x(-)/(2(4x-20)*3(-6x+3)))+(-2x4/(2(4x-20)*3(-6x+3)))=0



We calculate terms in parentheses: +(3x(-)/(2(4x-20)*3(-6x+3))), so:

3x(-)/(2(4x-20)*3(-6x+3))

We add all the numbers together, and all the variables

3x0/(2(4x-20)*3(-6x+3))

We multiply all the terms by the denominator


3x0

We add all the numbers together, and all the variables

3x

Back to the equation:

+(3x)





We calculate terms in parentheses: +(-2x4/(2(4x-20)*3(-6x+3))), so:

-2x4/(2(4x-20)*3(-6x+3))

We multiply all the terms by the denominator


-2x4

We add all the numbers together, and all the variables

-2x^4

We do not support expression: x^4

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