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4(3b-1)+6=5(2b-4)
We move all terms to the left:
4(3b-1)+6-(5(2b-4))=0
We multiply parentheses
12b-(5(2b-4))-4+6=0
We calculate terms in parentheses: -(5(2b-4)), so:We add all the numbers together, and all the variables
5(2b-4)
We multiply parentheses
10b-20
Back to the equation:
-(10b-20)
12b-(10b-20)+2=0
We get rid of parentheses
12b-10b+20+2=0
We add all the numbers together, and all the variables
2b+22=0
We move all terms containing b to the left, all other terms to the right
2b=-22
b=-22/2
b=-11
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