4(3b+2)+7=7(2b+1)+2b+4

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Solution for 4(3b+2)+7=7(2b+1)+2b+4 equation: 



4(3b+2)+7=7(2b+1)+2b+4

We move all terms to the left:

4(3b+2)+7-(7(2b+1)+2b+4)=0

We multiply parentheses

12b-(7(2b+1)+2b+4)+8+7=0



We calculate terms in parentheses: -(7(2b+1)+2b+4), so:

7(2b+1)+2b+4

We add all the numbers together, and all the variables

2b+7(2b+1)+4

We multiply parentheses

2b+14b+7+4

We add all the numbers together, and all the variables

16b+11

Back to the equation:

-(16b+11)



We add all the numbers together, and all the variables

12b-(16b+11)+15=0

We get rid of parentheses

12b-16b-11+15=0

We add all the numbers together, and all the variables

-4b+4=0

We move all terms containing b to the left, all other terms to the right

-4b=-4

b=-4/-4

b=1

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