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3(x-2)x=14
We move all terms to the left:
3(x-2)x-(14)=0
We multiply parentheses
3x^2-6x-14=0
a = 3; b = -6; c = -14;
Δ = b2-4ac
Δ = -62-4·3·(-14)
Δ = 204
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{204}=\sqrt{4*51}=\sqrt{4}*\sqrt{51}=2\sqrt{51}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{51}}{2*3}=\frac{6-2\sqrt{51}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{51}}{2*3}=\frac{6+2\sqrt{51}}{6} $
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