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4(3a+10)=5(2a+12)
We move all terms to the left:
4(3a+10)-(5(2a+12))=0
We multiply parentheses
12a-(5(2a+12))+40=0
We calculate terms in parentheses: -(5(2a+12)), so:We get rid of parentheses
5(2a+12)
We multiply parentheses
10a+60
Back to the equation:
-(10a+60)
12a-10a-60+40=0
We add all the numbers together, and all the variables
2a-20=0
We move all terms containing a to the left, all other terms to the right
2a=20
a=20/2
a=10
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