3.Y=x2+3x2+4

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Solution for 3.Y=x2+3x2+4 equation: 



3.=Y2+3Y^2+4

We move all terms to the left:

3.-(Y2+3Y^2+4)=0

We add all the numbers together, and all the variables

-(Y2+3Y^2+4)+3=0

We get rid of parentheses

-3Y^2-Y2-4+3=0

We add all the numbers together, and all the variables

-4Y^2-1=0

a = -4; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·(-4)·(-1)
Δ = -16
Delta is less than zero, so there is no solution for the equation

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