4(3a+1)-2(a-2)=13

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Solution for 4(3a+1)-2(a-2)=13 equation: 



4(3a+1)-2(a-2)=13

We move all terms to the left:

4(3a+1)-2(a-2)-(13)=0

We multiply parentheses

12a-2a+4+4-13=0

We add all the numbers together, and all the variables

10a-5=0

We move all terms containing a to the left, all other terms to the right

10a=5

a=5/10

a=1/2

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