(1)/(3)(6x-3)=(1)/(4)(8-4x)

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Solution for (1)/(3)(6x-3)=(1)/(4)(8-4x) equation: 



(1)/(3)(6x-3)=(1)/(4)(8-4x)

We move all terms to the left:

(1)/(3)(6x-3)-((1)/(4)(8-4x))=0



Domain of the equation: 3(6x-3)!=0

x∈R





Domain of the equation: 4(8-4x))!=0

x∈R



We add all the numbers together, and all the variables

1/3(6x-3)-(1/4(-4x+8))=0

We calculate fractions


(4x(-)/(3(6x-3)*4(-4x+8)))+(-3x6/(3(6x-3)*4(-4x+8)))=0



We calculate terms in parentheses: +(4x(-)/(3(6x-3)*4(-4x+8))), so:

4x(-)/(3(6x-3)*4(-4x+8))

We add all the numbers together, and all the variables

4x0/(3(6x-3)*4(-4x+8))

We multiply all the terms by the denominator


4x0

We add all the numbers together, and all the variables

4x

Back to the equation:

+(4x)





We calculate terms in parentheses: +(-3x6/(3(6x-3)*4(-4x+8))), so:

-3x6/(3(6x-3)*4(-4x+8))

We multiply all the terms by the denominator


-3x6

We add all the numbers together, and all the variables

-3x^6

We do not support expression: x^6

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