4(3/4x+1)=7(x+1/5)

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Solution for 4(3/4x+1)=7(x+1/5) equation: 



4(3/4x+1)=7(x+1/5)

We move all terms to the left:

4(3/4x+1)-(7(x+1/5))=0



Domain of the equation: 4x+1)!=0

x∈R



We add all the numbers together, and all the variables

4(3/4x+1)-(7(+x+1/5))=0

We multiply parentheses

12x-(7(+x+1/5))+4=0

We multiply all the terms by the denominator


12x*5))-(7(+x+1+4*5))=0

We add all the numbers together, and all the variables

12x*5))-(7(x+21))=0

We add all the numbers together, and all the variables

12x*5))-(7(x=0

Wy multiply elements

60x^2=0

a = 60; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·60·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{120}=0$

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