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4(3-x1)=3(2x-3)
We move all terms to the left:
4(3-x1)-(3(2x-3))=0
We add all the numbers together, and all the variables
4(-1x+3)-(3(2x-3))=0
We multiply parentheses
-4x-(3(2x-3))+12=0
We calculate terms in parentheses: -(3(2x-3)), so:We get rid of parentheses
3(2x-3)
We multiply parentheses
6x-9
Back to the equation:
-(6x-9)
-4x-6x+9+12=0
We add all the numbers together, and all the variables
-10x+21=0
We move all terms containing x to the left, all other terms to the right
-10x=-21
x=-21/-10
x=2+1/10
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