(x+3)(x-2)=(x+3)(x+3)-10

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Solution for (x+3)(x-2)=(x+3)(x+3)-10 equation: 



(x+3)(x-2)=(x+3)(x+3)-10

We move all terms to the left:

(x+3)(x-2)-((x+3)(x+3)-10)=0

We multiply parentheses ..

(+x^2-2x+3x-6)-((x+3)(x+3)-10)=0



We calculate terms in parentheses: -((x+3)(x+3)-10), so:

(x+3)(x+3)-10

We multiply parentheses ..

(+x^2+3x+3x+9)-10

We get rid of parentheses

x^2+3x+3x+9-10

We add all the numbers together, and all the variables

x^2+6x-1

Back to the equation:

-(x^2+6x-1)



We get rid of parentheses

x^2-x^2-2x+3x-6x-6+1=0

We add all the numbers together, and all the variables

-5x-5=0

We move all terms containing x to the left, all other terms to the right

-5x=5

x=5/-5

x=-1

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