4(3-x)-20=7(2+x)

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Solution for 4(3-x)-20=7(2+x) equation: 



4(3-x)-20=7(2+x)

We move all terms to the left:

4(3-x)-20-(7(2+x))=0

We add all the numbers together, and all the variables

4(-1x+3)-(7(x+2))-20=0

We multiply parentheses

-4x-(7(x+2))+12-20=0



We calculate terms in parentheses: -(7(x+2)), so:

7(x+2)

We multiply parentheses

7x+14

Back to the equation:

-(7x+14)



We add all the numbers together, and all the variables

-4x-(7x+14)-8=0

We get rid of parentheses

-4x-7x-14-8=0

We add all the numbers together, and all the variables

-11x-22=0

We move all terms containing x to the left, all other terms to the right

-11x=22

x=22/-11

x=-2

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