4(3-v)-v=6+3(v+2)

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Solution for 4(3-v)-v=6+3(v+2) equation: 



4(3-v)-v=6+3(v+2)

We move all terms to the left:

4(3-v)-v-(6+3(v+2))=0

We add all the numbers together, and all the variables

4(-1v+3)-v-(6+3(v+2))=0

We add all the numbers together, and all the variables

-1v+4(-1v+3)-(6+3(v+2))=0

We multiply parentheses

-1v-4v-(6+3(v+2))+12=0



We calculate terms in parentheses: -(6+3(v+2)), so:

6+3(v+2)

determiningTheFunctionDomain
3(v+2)+6

We multiply parentheses

3v+6+6

We add all the numbers together, and all the variables

3v+12

Back to the equation:

-(3v+12)



We add all the numbers together, and all the variables

-5v-(3v+12)+12=0

We get rid of parentheses

-5v-3v-12+12=0

We add all the numbers together, and all the variables

-8v=0

v=0/-8

v=0

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