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x+5/3x=800
We move all terms to the left:
x+5/3x-(800)=0
Domain of the equation: 3x!=0We multiply all the terms by the denominator
x!=0/3
x!=0
x∈R
x*3x-800*3x+5=0
Wy multiply elements
3x^2-2400x+5=0
a = 3; b = -2400; c = +5;
Δ = b2-4ac
Δ = -24002-4·3·5
Δ = 5759940
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5759940}=\sqrt{4*1439985}=\sqrt{4}*\sqrt{1439985}=2\sqrt{1439985}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2400)-2\sqrt{1439985}}{2*3}=\frac{2400-2\sqrt{1439985}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2400)+2\sqrt{1439985}}{2*3}=\frac{2400+2\sqrt{1439985}}{6} $
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