4(3-3k)=6(2k-2)

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Solution for 4(3-3k)=6(2k-2) equation: 



4(3-3k)=6(2k-2)

We move all terms to the left:

4(3-3k)-(6(2k-2))=0

We add all the numbers together, and all the variables

4(-3k+3)-(6(2k-2))=0

We multiply parentheses

-12k-(6(2k-2))+12=0



We calculate terms in parentheses: -(6(2k-2)), so:

6(2k-2)

We multiply parentheses

12k-12

Back to the equation:

-(12k-12)



We get rid of parentheses

-12k-12k+12+12=0

We add all the numbers together, and all the variables

-24k+24=0

We move all terms containing k to the left, all other terms to the right

-24k=-24

k=-24/-24

k=1

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