-9+7/6b=7/12b

Solution for -9+7/6b=7/12b equation:

-9+7/6b=7/12b

We move all terms to the left:

-9+7/6b-(7/12b)=0


Domain of the equation: 6b!=0

b!=0/6

b!=0

b∈R



Domain of the equation: 12b)!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

7/6b-(+7/12b)-9=0

We get rid of parentheses

7/6b-7/12b-9=0

We calculate fractions


84b/72b^2+(-42b)/72b^2-9=0

We multiply all the terms by the denominator


84b+(-42b)-9*72b^2=0

Wy multiply elements

-648b^2+84b+(-42b)=0

We get rid of parentheses

-648b^2+84b-42b=0

We add all the numbers together, and all the variables

-648b^2+42b=0

a = -648; b = 42; c = 0;
Δ = b2-4ac
Δ = 422-4·(-648)·0
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-42}{2*-648}=\frac{-84}{-1296}
=7/108
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+42}{2*-648}=\frac{0}{-1296}
=0
$