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24x^2+14x-5=4x^2+8x+3
We move all terms to the left:
24x^2+14x-5-(4x^2+8x+3)=0
We get rid of parentheses
24x^2-4x^2+14x-8x-3-5=0
We add all the numbers together, and all the variables
20x^2+6x-8=0
a = 20; b = 6; c = -8;
Δ = b2-4ac
Δ = 62-4·20·(-8)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-26}{2*20}=\frac{-32}{40} =-4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+26}{2*20}=\frac{20}{40} =1/2 $
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