4(3+y)=16

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Solution for 4(3+y)=16 equation: 



4(3+y)=16

We move all terms to the left:

4(3+y)-(16)=0

We add all the numbers together, and all the variables

4(y+3)-16=0

We multiply parentheses

4y+12-16=0

We add all the numbers together, and all the variables

4y-4=0

We move all terms containing y to the left, all other terms to the right

4y=4

y=4/4

y=1

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