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5/6x+15/8x=8
We move all terms to the left:
5/6x+15/8x-(8)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 8x!=0We calculate fractions
x!=0/8
x!=0
x∈R
40x/48x^2+90x/48x^2-8=0
We multiply all the terms by the denominator
40x+90x-8*48x^2=0
We add all the numbers together, and all the variables
130x-8*48x^2=0
Wy multiply elements
-384x^2+130x=0
a = -384; b = 130; c = 0;
Δ = b2-4ac
Δ = 1302-4·(-384)·0
Δ = 16900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16900}=130$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(130)-130}{2*-384}=\frac{-260}{-768} =65/192 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(130)+130}{2*-384}=\frac{0}{-768} =0 $
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