4(3+u)-u=6+3(u+3)

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Solution for 4(3+u)-u=6+3(u+3) equation: 



4(3+u)-u=6+3(u+3)

We move all terms to the left:

4(3+u)-u-(6+3(u+3))=0

We add all the numbers together, and all the variables

4(u+3)-u-(6+3(u+3))=0

We add all the numbers together, and all the variables

-1u+4(u+3)-(6+3(u+3))=0

We multiply parentheses

-1u+4u-(6+3(u+3))+12=0



We calculate terms in parentheses: -(6+3(u+3)), so:

6+3(u+3)

determiningTheFunctionDomain
3(u+3)+6

We multiply parentheses

3u+9+6

We add all the numbers together, and all the variables

3u+15

Back to the equation:

-(3u+15)



We add all the numbers together, and all the variables

3u-(3u+15)+12=0

We get rid of parentheses

3u-3u-15+12=0

We add all the numbers together, and all the variables

-3!=0

There is no solution for this equation

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