1/6(4x-6)=1/3(7x+2)

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Solution for 1/6(4x-6)=1/3(7x+2) equation: 



1/6(4x-6)=1/3(7x+2)

We move all terms to the left:

1/6(4x-6)-(1/3(7x+2))=0



Domain of the equation: 6(4x-6)!=0

x∈R





Domain of the equation: 3(7x+2))!=0

x∈R



We calculate fractions


(3x7/(6(4x-6)*3(7x+2)))+(-6x4/(6(4x-6)*3(7x+2)))=0



We calculate terms in parentheses: +(3x7/(6(4x-6)*3(7x+2))), so:

3x7/(6(4x-6)*3(7x+2))

We multiply all the terms by the denominator


3x7

We add all the numbers together, and all the variables

3x^7

We do not support expression: x^7

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