4(3+u)-4=6+3(u+2)

Solution for 4(3+u)-4=6+3(u+2) equation:

4(3+u)-4=6+3(u+2)

We move all terms to the left:

4(3+u)-4-(6+3(u+2))=0

We add all the numbers together, and all the variables

4(u+3)-(6+3(u+2))-4=0

We multiply parentheses

4u-(6+3(u+2))+12-4=0


We calculate terms in parentheses: -(6+3(u+2)), so:

6+3(u+2)

determiningTheFunctionDomain
3(u+2)+6

We multiply parentheses

3u+6+6

We add all the numbers together, and all the variables

3u+12

Back to the equation:

-(3u+12)


We add all the numbers together, and all the variables

4u-(3u+12)+8=0

We get rid of parentheses

4u-3u-12+8=0

We add all the numbers together, and all the variables

u-4=0

We move all terms containing u to the left, all other terms to the right

u=4