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5/6x+3x=23
We move all terms to the left:
5/6x+3x-(23)=0
Domain of the equation: 6x!=0We add all the numbers together, and all the variables
x!=0/6
x!=0
x∈R
3x+5/6x-23=0
We multiply all the terms by the denominator
3x*6x-23*6x+5=0
Wy multiply elements
18x^2-138x+5=0
a = 18; b = -138; c = +5;
Δ = b2-4ac
Δ = -1382-4·18·5
Δ = 18684
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{18684}=\sqrt{36*519}=\sqrt{36}*\sqrt{519}=6\sqrt{519}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-138)-6\sqrt{519}}{2*18}=\frac{138-6\sqrt{519}}{36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-138)+6\sqrt{519}}{2*18}=\frac{138+6\sqrt{519}}{36} $
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