4(3+5x)=16+56-4(2x-1)

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Solution for 4(3+5x)=16+56-4(2x-1) equation:



4(3+5x)=16+56-4(2x-1)
We move all terms to the left:
4(3+5x)-(16+56-4(2x-1))=0
We add all the numbers together, and all the variables
4(5x+3)-(16+56-4(2x-1))=0
We multiply parentheses
20x-(16+56-4(2x-1))+12=0
We calculate terms in parentheses: -(16+56-4(2x-1)), so:
16+56-4(2x-1)
determiningTheFunctionDomain -4(2x-1)+16+56
We add all the numbers together, and all the variables
-4(2x-1)+72
We multiply parentheses
-8x+4+72
We add all the numbers together, and all the variables
-8x+76
Back to the equation:
-(-8x+76)
We get rid of parentheses
20x+8x-76+12=0
We add all the numbers together, and all the variables
28x-64=0
We move all terms containing x to the left, all other terms to the right
28x=64
x=64/28
x=2+2/7

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