1,6x-(x-2,8)=(0,2x+1,5)-0,7

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Solution for 1,6x-(x-2,8)=(0,2x+1,5)-0,7 equation: 



1.6x-(x-2.8)=(0.2x+1.5)-0.7

We move all terms to the left:

1.6x-(x-2.8)-((0.2x+1.5)-0.7)=0

We get rid of parentheses

1.6x-x-((0.2x+1.5)-0.7)+2.8=0



We calculate terms in parentheses: -((0.2x+1.5)-0.7), so:

(0.2x+1.5)-0.7

We get rid of parentheses

0.2x+1.5-0.7

We add all the numbers together, and all the variables

0.2x+0.8

Back to the equation:

-(0.2x+0.8)



We add all the numbers together, and all the variables

0.6x-(0.2x+0.8)+2.8=0

We get rid of parentheses

0.6x-0.2x-0.8+2.8=0

We add all the numbers together, and all the variables

0.4x+2=0

We move all terms containing x to the left, all other terms to the right

0.4x=-2

x=-2/0.4

x=-5

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