4(3+2x)=7-2(3x+1)

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Solution for 4(3+2x)=7-2(3x+1) equation: 



4(3+2x)=7-2(3x+1)

We move all terms to the left:

4(3+2x)-(7-2(3x+1))=0

We add all the numbers together, and all the variables

4(2x+3)-(7-2(3x+1))=0

We multiply parentheses

8x-(7-2(3x+1))+12=0



We calculate terms in parentheses: -(7-2(3x+1)), so:

7-2(3x+1)

determiningTheFunctionDomain
-2(3x+1)+7

We multiply parentheses

-6x-2+7

We add all the numbers together, and all the variables

-6x+5

Back to the equation:

-(-6x+5)



We get rid of parentheses

8x+6x-5+12=0

We add all the numbers together, and all the variables

14x+7=0

We move all terms containing x to the left, all other terms to the right

14x=-7

x=-7/14

x=-1/2

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