4(3+2/3y)+5y=35

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Solution for 4(3+2/3y)+5y=35 equation: 



4(3+2/3y)+5y=35

We move all terms to the left:

4(3+2/3y)+5y-(35)=0



Domain of the equation: 3y)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

4(2/3y+3)+5y-35=0

We add all the numbers together, and all the variables

5y+4(2/3y+3)-35=0

We multiply parentheses

5y+8y+12-35=0

We add all the numbers together, and all the variables

13y-23=0

We move all terms containing y to the left, all other terms to the right

13y=23

y=23/13

y=1+10/13

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