-4(-4u+3)-u=6(u-4)-3

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Solution for -4(-4u+3)-u=6(u-4)-3 equation: 



-4(-4u+3)-u=6(u-4)-3

We move all terms to the left:

-4(-4u+3)-u-(6(u-4)-3)=0

We add all the numbers together, and all the variables

-1u-4(-4u+3)-(6(u-4)-3)=0

We multiply parentheses

-1u+16u-(6(u-4)-3)-12=0



We calculate terms in parentheses: -(6(u-4)-3), so:

6(u-4)-3

We multiply parentheses

6u-24-3

We add all the numbers together, and all the variables

6u-27

Back to the equation:

-(6u-27)



We add all the numbers together, and all the variables

15u-(6u-27)-12=0

We get rid of parentheses

15u-6u+27-12=0

We add all the numbers together, and all the variables

9u+15=0

We move all terms containing u to the left, all other terms to the right

9u=-15

u=-15/9

u=-1+2/3

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