4(3+)-x=6+3(x+2)

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Solution for 4(3+)-x=6+3(x+2) equation: 



4(3+)-x=6+3(x+2)

We move all terms to the left:

4(3+)-x-(6+3(x+2))=0

We add all the numbers together, and all the variables

-x-(6+3(x+2))+40=0

We add all the numbers together, and all the variables

-1x-(6+3(x+2))+40=0



We calculate terms in parentheses: -(6+3(x+2)), so:

6+3(x+2)

determiningTheFunctionDomain
3(x+2)+6

We multiply parentheses

3x+6+6

We add all the numbers together, and all the variables

3x+12

Back to the equation:

-(3x+12)



We get rid of parentheses

-1x-3x-12+40=0

We add all the numbers together, and all the variables

-4x+28=0

We move all terms containing x to the left, all other terms to the right

-4x=-28

x=-28/-4

x=+7

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