3(y+1)-7=3(y-1)+y

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Solution for 3(y+1)-7=3(y-1)+y equation: 



3(y+1)-7=3(y-1)+y

We move all terms to the left:

3(y+1)-7-(3(y-1)+y)=0

We multiply parentheses

3y-(3(y-1)+y)+3-7=0



We calculate terms in parentheses: -(3(y-1)+y), so:

3(y-1)+y

We add all the numbers together, and all the variables

y+3(y-1)

We multiply parentheses

y+3y-3

We add all the numbers together, and all the variables

4y-3

Back to the equation:

-(4y-3)



We add all the numbers together, and all the variables

3y-(4y-3)-4=0

We get rid of parentheses

3y-4y+3-4=0

We add all the numbers together, and all the variables

-1y-1=0

We move all terms containing y to the left, all other terms to the right

-y=1

y=1/-1

y=-1

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